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Our expert and friendly tutors can help you learn algebra with ease! Please call us tollfree at 1.877.TUTOR18 or register online if you need help with Algebra.
- Linear equations in one variable
- Absolute value equations and inequalities
- Radical expressions and rational exponents
- Factorization of polynomials
- Relations and functions
- Quadratic equations
- Matrices and their operations
- Linear programming problems
- Arithmetic and geometric progression
- Complex numbers and their properties
- Conic sections and equation of a conic in (h, k) form
Our proven 4-step learning approach enables students to understand mathematical concepts and apply these concepts to successfully solve practical problems. We equip you with tips for tricky questions, and teach shortcuts to improve testing speed and mental calculations.
Our examples below illustrate our comprehensive explanations with all steps. This means: Better understanding and Greater success in Algebra for YOU
| 1. |
Terry has $2.35 in nickels and dimes. If he has a total of thirty two coins, how many of each type of coin does he have?
Before answering to this question we must know the following conversions.
1 dollar = 100 cents
1 dime = 10 cents
1 nickel = 5 cents.
Let the number dimes be x, then the number of nickels is  .
Therefore,
The value of x dimes is $0.10x and,
The value of  nickels is $0.05 ( ).
We have been given that the total amount Terry has with him is $2.35.
Therefore,
So, the number of dimes is 15 and the number of nickels is 17.
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| 2. |
Find the real values of x and y:
Given,
Two complex numbers are said to be equal if the corresponding real parts are equal and the corresponding imaginary parts are equal.
So, 
Compare the real and imaginary parts on both sides, then we get,
 ..... (1)
And 
 ...... (2)
2 x (2)  ....... (3)
(3) - (1)
From (1), we get
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| 3. |
| Solve for x: |
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We are asked to find the value of the variable x. First we can find the LCM of the denominators on the left hand side of the expression.
i.e.
LCM of  and  is 
Therefore,
 ,
since  is a common term.
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4.
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| Find: |
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Simplify the terms in the given expression separately.
i.e.
 ,
And,
Therefore,
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