learn math competition solutions

Every individual needs food, space, protection from enemies and ij adverse weather conditions, and mate. :i It is not easy to get these requirements \ as the earth is crowded with life. There ?is competition among the organisms i;for their needs, and it may be quite :: intense. No habitat is peaceful. The ; animals occupying it a..

community competition

This is the interaction between individuals of different species in a community. It is also called interspecific competition. For example, dandelion and daisy plants growing on a grass lawn or sheep and rabbits grazing together. The main result of competition within a community is that one species will flour..

competitive inhibition

Solved Problems 1. Explain enzyme inhibition. What are the different inhibitions? Solution: A substance that binds with an enzyme and results in a decrease in catalytic activity of the enzyme is called an enzyme inhibitor, and the process is known as enzyme inhibition. The latter can provide an insight into the mechanism of e..

solution

Trigonometric Functions and Identities LEVEL-I 1. Here L.H.S. $\sin^{2}12^{\circ}+\sin^{2}21^{\circ}+(\sin^{2}39^{\circ}-\sin^{2}9^{\circ})+(\sin^{2}48^{\circ}-\sin^{2}18^{\circ})$ $\Rightarrow\sin^{2}12^{\circ}+\sin^{2}21^{\circ}+\sin(48^{\circ}).\sin(30^{\circ})+\sin(30^{\circ}).\sin(66^{\circ})$ ..

solutions

LEVEL II 1. We know from Napier's analogy that : $\qquad\qquad{\displaystyle \tan\left(\frac{B-C}{2}\right)=\frac{b-c}{b+c}\cot\frac{A}{2}}$ $\qquad\qquad{\displaystyle \tan\left(\frac{A-B}{2}\right)=\frac{a-b}{a+b}\cot\frac{C}{2}}$ $\qquad\qquad{\displaystyle \tan\left(\frac{C-A}{2}\right)=\frac{c-a}{c+a..

Solution

="font54" style="font-style: italic;"> x sin a) dx J oosx J cosx J, . - '' . : - = cos a jdx + sin a Jtan x dx = (cos a) x + sin a log | sec x \ + c 4. Let x-a = t => x = t + a and dx = dt "..

Solutions

The greatest common factor is 8 6Ans : Given equation is xy + 3y 2x 6 = 0 arrange them in an order now. We get xy 2x + 3y 6 = 0 x (y 2) + 3 (y 2) = 0 (x + 3) (y 2) = 0 So here (x + 3) and ( y 2) are the factors 7Ans: Given that. 5(A) +6(O) =$40 Each orange is $3 So we get 5(A) + 6(O) = $40 5(A) + 6(3) = 40 5(A) + 18 ..

Solution

="margin-bottom: 0.0001pt; text-indent: 0in; line-height: 17pt; background: none repeat scroll 0% 0% transparent;"> K '9- Fig. 7.10 (iv) cos Let tan '4 = 0. Th..

particular solution

By assigning particular values to $a$ and $b$, say $a=2$ and $b=5$ in (2) we get $f (x,\ y,\ 2,5)=0$. Such a solution is called a "Particular solution'' of the differential equation. ..

solution of triangles

In a triangle there are six elements. $viz$. three sides $a,b,c$ and three angles. $A,B,C$ when any three of these six elements (except all the three angles) of a triangle are given, the triangle is known completely; that is the other three elements can be expressed in terms of the given elements and can be evaluated. This process is called the..

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