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Mathematical Reasoning
Mathematical reasoninghelps in solving many mathematical puzzle,this can increase our capicity of solving.The operations involved are addition,subtraction,multiplication and division.The puzzles can be solved easily and reasoning can be given based..
Mathematical Expressions
Mathematical expressions are the combination of mathematical symbols or numbers or both. Every expression contains important elements called variables. Expression generally does not contain equality sign, if it has an equality sign then it represented as an equation. So, In th..
Solution
> = . * M [log | sin (x - a) | - log | sin (x - fc) [ ] + c = log + * sm {a - b) sin (a - b) sm (x - b) 11. ^ = f~-dx [For alternative solution see Q. 3 in solved Ex. 21 J1 + cot x J sin x + cos x x 1 = f si" x (cos x - sin x) ^ _ fsin 2x -2sin 2 x ^ J (cos x + sin x) (cos x - s..
Math
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Mathematical Formulation of Linear Programming
Linear Programming The standard form of the linear programming problem (LPP) is used to develop the procedure for solving a general programming problem. A general LPP is of the form Maximize (or minimize) Z = c 1 x 1 + c 2 x 2 + + c n x n (1) Subject to a 11 x 1 + a 12 x 2 + . . . . ..
Math problems | Solve Math Problems
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Solve Free Math Problems
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Solving math ratios
Finally, lets take a look at comparing two ratios In order to compare two ratios we first need to convert the ratios into fractions with same denominator ( very important ) For example, consider the ratios 2 : 7 and 1 : 3 Here we have to compare the fractions $$ \frac{2}{7}$$ and $$ \frac{1}{3}..
Get Free Math Tutoring Online
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Q 5: Out of 120 students who secured first class marks in Mathematics or English, 70 obtained first class in Mathematics and 31 in English and Mathematics. How many students secured first class marks in English only?
Solution: Let n(M) = number of students who secured first class marks in Mathematics n(E) = number of students who secured first class marks in English n(M) = 70 n(M $\cup$ E) = 120 n(M $\cap$ E) = 31 Using n(M $\cup$ E) = n(M) + n(E) - n(M $\cap$ E) ..