Algebra 2 Problems can be tricky. To solve algebra 2 problems one needs rigor and application. Sometimes you get baffled by some algebra 2 problems and you wonder if the one you are trying to solve is an algebra 2 answer at all, whether the algebra 2 problem can ever be solved.
Tutors at TutorNext can help you get to the root of the problem. Any problem that befuddles you is explained step by step by our expert tutors.
Online Algebra 2 Problems
Imagine you found this free algebra 2 problem as a part of some online algebra 2 problems:
A company's sales were zooming up. They already had 5 million customers. And just yesterday their 6 millionth customer had signed in and the company was rejoicing. But then something strange happened. When customer number 6,000,001came up for signing, their system crashed. What happened here? Before we find out what happened, let's look at the how the login for a user happens.
The company has a login user interface (UI). Users need to submit their username and password to login. When a new user joins, he or she can choose his/her userid. The password, however, is system generated which a user needs to remember. The password has a mixed but fixed format: The first two entries are lower case alphabets with no repeats. In either place the alphabet should not be the alphabet o so as not to confuse with the number zero. The next four items that a user needs to enter as part of the password must be digits but without any restrictions.
Fine. But why did the system crash? Let's find out.
Algebra 2 Problem Solved
TutorNext online tutors will tell you that this is a simple permutation problem; have this algebra 2 problem solved by incorporating concepts of permutation.
Look at the way the password is being structured. There are only 6 million distinct passwords that can be made with the given structure of 2 letters (not repeating and without the alphabet o) and 4 digits (with no restriction in each digit).
Here is how the computation goes:
25P2 for the first two letters and 10X10X10X10 for the next four digits.
= (25!/23!) X 104
=25X24X10X10X10X10
=6,000,000
That is, 6 million passwords. If one attempts to make the 6,000,001th password, the system will crash.
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