One of the most important topics in math is linear equations. Solving linear equations becomes easy and less time 
consuming with TutorNext tutors. Students can learn how to solve linear equations online. An equation is a mathematical structure that deals with the equality of two expressions whereas any equation when graphed produces a straight line is a linear equation. This is a concept which is covered in the study of basic math and also advance math as well.
As solving linear equations is such an important part of solving math problems and solving equations , our tutors try it every possible to make it simpler and easy to understand for you. Now get online linear equation help from highly qualified and well trained TutorNext Tutors.
Below are stated few examples to demonstrate how to solve linear equations.
Solving Linear Equations Online
Students can learn how to solve linear equations by Solving Linear Equations online resource. There are ample solved examples observing which students can learn to solve similar problems.
$\frac{bx}{ay}$ - $\frac{ay}{b}$ + a + b = 0
bx - ay + 2ab = 0
Answer:
Consider $\frac{bx}{ay}$ - $\frac{ay}{b}$ + a + b = 0
$\frac{bx}{ay}$ - $\frac{ay}{b}$ = -(a + b)
b2x - a2y = -ab(a + b) …………(1)
bx - ay = -2ab …………(2) x a
b2x - a2y = -ab(a + b) ………….(1)
abx - a2y = -2a2b …………(3)
(1)-(3) gives x(b2 - ab) = -ab(a + b) + 2a2b
bx(b - a) = a2b - ab2 = ab(a - b)
bx(b - a) = -ab(b - a)
x = $\frac{-ab(b-a)}{b(b-a)}$ = -a
bx - ay + 2ab = 0
b(-a) - ay + 2ab = 0
-ay + ab = 0; -ay = -ab
y = $\frac{-ab}{a}$ = b
Online Linear Equation Examples
Solve the Linear equation :
$\frac{7x-2y}{xy}$ = 5; $\frac{8x+7y}{xy}$ = 15
Answer: This example help us to understand the concept more clearly.
$\frac{7x-2y}{xy}$ = $\frac{7x}{xy}$ - $\frac{2y}{xy}$ = 5; $\frac{7}{y}$ - $\frac{2}{x}$ = 5
$\frac{8x-7y}{xy}$ = $\frac{8x}{xy}$ - $\frac{7y}{xy}$ = 5; $\frac{8}{y}$ - $\frac{7}{x}$ = 5
Let
7a - 2b = 5 x 7
48a - 14b = 36 ……..(3)
8a + 7b = 15 x 2
16a + 14b = 30 ………(4)
(3 + 4) gives
65a = 65
a = 1
7a - 2b = 5
7 - 2b = 5
-2b = -2
b = 1
or y = 1
or x = 1
The students can get more solved examples and practice problems on math problems page and practice how to solve linear equations.
Linear Equations Practice Problems
Solve :
$\frac{2}{\sqrt{x}}$ + $\frac{3}{\sqrt{y}}$ = 2; $\frac{4}{\sqrt{x}}$ - $\frac{9}{\sqrt{y}}$ = -1
Answer:
$\frac{2}{\sqrt{x}}$ + $\frac{3}{\sqrt{y}}$ = 2 --------------- (1)
$\frac{4}{\sqrt{x}}$ - $\frac{9}{\sqrt{y}}$ = -1 ----------------- (2)
Let $\frac{1}{\sqrt{x}}$ = a; $\frac{1}{\sqrt{y}}$ = b
4a-9b=-1
4a+6b=4 ……..(3)
4a-9b=-1 ………(4)
(3)-(4) 15b=5 b= $\frac{1}{3}$
2a+3b=2
2a+3 $\frac{1}{3}$ =2; 2a+1=2; 2a=1; a= $\frac{1}{2}$
a = $\frac{1}{2}$; b = $\frac{1}{3}$
a = $\frac{1}{x}$ = $\frac{1}{2}$ or $\sqrt{x}$ = 2; x = 4
b= $\frac{1}{y}$ = $\frac{1}{3}$ or $\sqrt{y}$ = 3; y = 9
Students can get help with practice problems and homework problems on the math homework help page.