Get our Online Tutoring session
at Affordable Price
Get our Online Tutoring session
at Affordable Price

(Hurry! This offer expires soon!)

Numerical Problems of Compound Interest

Q 1. Find the Compound Interest when Principal is Rs. 7000, Rate is 6% P.a. and Period is 2 Years.

Answer:

Step1. Given P = Rs.7000

r = 6% p.a.

n = 2years

Compound Interest(b)

Step2. Substitute the corresponding values in the formula

A = 7000( 1 + 6 )2
100

Step3. Simplify and find the value of A.

A = 7000( 1 + 106 )2
100
A= 7000 x 106 x 106
100 100

A =7865.20.

Step4.

Compound Interest = Amount (A) – Principal (P)

= Rs.7,865.20 – Rs.7,000

$\therefore$ Compound Int. = Rs. 865.20.

Q 2. Jack Borrowed a Sum of Rs. 700, from a Financial Company at C.i. R 16.5% P.a. for 2years. Find the Amount he has to Pay at the End of 2 Years.

Answer:

Step 1. Given P = Rs.700

r = 16.5% p.a.

n = 2years

Compound Interest(c)

A = 700( 1 + 16.5)2
100
A = 700( 116.5)2
100
A= 700 x 116.5 x 116.5
100 100

A =950.05.

$\therefore$ Jack has to pay 950.05 at the end of 2 years.

Q 3. Sara Deposited Rs.2000 at C.i. 10% P.a. for 3 Years. Find the Compound Interest he Gets after 3 Years.

Answer:

Given P = Rs.2000

r = 10% p.a.

n = 3 years

Compound Interest(d)

A = 2000( 1 + 10 )3
100
A = 2000( 1 + 1)3
10
A = 2000(11)3
10
A = 2000 x 11 x 11 x 11
10 10 10

A = 2662.

Compound Interest = Amount (A) – Principal (P)

= Rs.2662 – Rs.2000

$\therefore$ Compound Int. = Rs.662

$\therefore$ Compound Interest Sara gets after 3 years = Rs. 662.

Q 4. Kate Invested Rs.1000 in a Financial Company and Received Rs.1331 after 3 Years. Find the Interest Percent per Annum.

Answer: Given P = Rs.1000

n = 3 years

A = Rs.1331

r = ?

Compound Interest(f)

$\therefore$ 1331 = 1000( 1 + r / 100 )3

$\therefore$ 1331 / 1000 = ( 1 + r / 100 )3

$\therefore$ ( 11 / 10 )3 = ( 1 + r / 100 )3
$\therefore$ ( 1 + 1 / 10 )3 = ( 1 + r / 100 )3

Since the powers are same we can compare their powers.

$\therefore$ ( 1 + 1 / 10 ) = ( 1 + r / 100 )
$\therefore$ 1 + 1 / 10 = 1 + r / 100

$\therefore$ 1 / 10 = r / 100

$\therefore$ r = 100 / 10

$\therefore$ r = 10

$\therefore$ Rate of interest = 10% p.a.

Related Tags

free Numerical Problems of Compound Interest , online Numerical Problems of Compound Interest , solved Numerical Problems of Compound Interest