| 3. |
Find the gradient of the curves at their points of intersection. Hence find the angles at which the curves cut.
To find the points of intersection we can solve the given equations simultaneously.
We have been given that , substituting this in ,
We have,  When 
Now we need to fin the gradients, given

Therefore,  Therefore,
At (0, 0), and at (4, 2), 
Again,

Therefore, Therefore, At (0, 0), 
It is clear that at (0, 0) the curves cut at right angles as the tangents to the curves at (0, 0) are at right angles to each other, being parallel and perpendicular to the x-axis respectively. At the point (4, 2) the angle of intersection is given by the equation 
|